Because of their spontaneous polarization, ferroelectrics exhibit hysteresis properties: their response to an external field (the dependence of the polarization $P$ vs. the external electric field $E$) depends on their previous state.
Consider a ferroelectric material that had polarization $P_1$ in an external electric field $E_1$ at the initial time. The field was then increased to $E_2$, and the polarization increased to $P_2$, following the law $P_-(E)$. Then the field was again reduced to $E_1$, and the polarization of the ferroelectric returned to its initial state following the law $P_+(E)$.
Now consider a hysteresis loop of one of the most widely used ferroelectric materials, barium titanate (BTO). The loop is plotted on a figure below.
On the horizontal axis is the external electric field strength in $kV/cm$, on the vertical axis is the polarization of the segnetoelectric in $μC/cm^2$.
Suppose a large $(>300~V)$ negative voltage is applied to a thin BTO film of thickness $d=10~µm$ and area $S=1~cm^2$. Then it's changed to a large positive voltage and finally returned back.
Now suppose an alternating voltage with effective voltage $V_\mathrm{eff}=220~V$ and frequency $\nu=50~Hz$ is applied to the film.