After integrating the second equation we have:
\[ \dot{Y} = -\frac{eB}{m} (X-X_0).\]Thus, with substitution $X \to X + X_0$:
\[\ddot{X}+\left( \frac{eB}{m} \right)^2 X = 0\]
Let's substitute the solution $x=A e^{i \omega t}$ correspoing to driven oscillations
\[ A \left( (i \omega)^2 + \omega_0^2 \right) e^{i \omega t}= - \frac{eE}{m} e^{i \omega t}\]There is resonance when $\omega=\omega_0$.
If a system can absorb an EM field with a frequency of $\omega$, then it can absorb photons with an energy of $\hbar \omega$. Then, the system can also absorb a photon with energy $n \hbar \omega$ due to the absorption of multiples portions of energy each equal to $\hbar \omega$.
There are two cyclotron resonant scattering features (e.g. 272 rev) on the graph: $E_\mathrm{cycl}=26~\text{keV}$ and $2E_\mathrm{cycl}=50~\text{keV}$. So, the magnetic field
\[ B = \frac{m E_\mathrm{cycl}}{\hbar e}=2 \cdot 10^{8}~\text{T}\]