| 1 $$\left|\vec v\right|^2 = v_x^2+v_y^2$$ | 0.50 |
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| 1 $$\left|\vec a\right| = \sqrt{\left|\vec a_\parallel\right|^2+\left|\vec a_\perp\right|^2}$$ | 0.50 |
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| 1 Доказано, что $\left(\vec v \cdot \vec a\right) = \left(\vec v\cdot \vec a_\parallel\right)$. | 0.50 |
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| 2 Доказано, что $\left|\left(\vec v \cdot \vec a\right) \right|= \left|\vec v\right|\cdot \left|\vec a_\parallel\right|$. | 0.50 |
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| 1 $$\left|\vec a_\parallel\right| = \frac{\left|\left(\vec v \cdot \vec a\right) \right|}{\left|\vec v\right|}$$ | 0.50 |
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| 2 $$\left|\vec a_\perp\right| = \sqrt{\left|\vec a\right|^2 - \frac{\left(\vec v \cdot \vec a\right) ^2}{\left|\vec v\right|^2}}$$ | 0.50 |
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1
Доказано и получено: $$A=2$$ |
0.50 |
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| 1 $$\frac{d\left(\vec v\cdot \vec v\right)}{dt} = 2\left(\vec v \cdot \vec a\right)$$ | 1.00 |
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| 1 $$v_x = v\cos\varphi$$$$v_y = v\sin\varphi$$ | 2 × 0.50 |
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| 1 $$\frac{d\left(\vec v\cdot \vec v\right)}{dt} = 2v\dot v$$ | 1.00 |
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| 1 $$a_x = \dot v \cos\varphi - v\sin\varphi\dot \varphi$$$$a_y = \dot v \sin\varphi + v\cos\varphi\dot\varphi$$ | 2 × 0.50 |
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| 1 $$\left|\vec a_\perp\right| = v\left|\dot\varphi\right|$$ | 1.00 |
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| 1 $$\dot v = \frac{\left(\vec v\cdot\vec a\right)}{v}$$ | 0.50 |
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| 1 $$\left|\dot\varphi\right| = \frac{1}{v}\sqrt{\left|\vec a\right|^2 - \frac{\left(\vec v \cdot \vec a\right) ^2}{v^2}}$$ | 1.00 |
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