| 1 Correct method is described | 0.60 |
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| 2 \[S \in [0.058,0.088]~\mathrm{cm}^2\] | 0.20 |
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| 1 Towards open end | 0.20 |
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| 1 Measurements of $x$ and $x_0$ | 5 × 0.40 |
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| 2 \[V_\mathrm{max} - V_\mathrm{min} \geq 6~\mathrm{ml}\] | 0.50 |
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| 1 Graph is plotted | 1.00 |
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| 2 Labels of axes are missing | -0.20 |
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| 3 Poor scale | -0.20 |
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| 4 Poor ticks | -0.20 |
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| 5 There is no fitting line | -0.20 |
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1
Explicetly stated that $\mathrm{slope}$ is equal to \[\frac{1}{S} \cdot \dfrac{\frac{\Delta T}{T_0 + 273^\circ\text{C}}}{1+\frac{\Delta T}{T_0 + 273^\circ\text{C}}}\] |
0.20 |
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| 2 $\mathrm{slope} \in [0.3,0.8]~\mathrm{cm}/\mathrm{ml}$ | 0.20 |
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| 3 \[T_\mathrm{h} \in [27,36]^\circ\text{C}\] | 0.40 |
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| 4 \[\frac{\Delta T}{T_0 + 273^\circ\text{C}}\in[0.024,0.054]\] | 0.20 |
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| 1 Value of $x_0$ is specified | 0.10 |
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| 2 Measurements of $x$ on $t$ | 12 × 0.10 |
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| 3 Total duration is greater than $5~\mathrm{min}$ | 0.50 |
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| 1 \[\ln (x-x_0) = C - \frac{t}{\tau}\] | 1.00 |
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| 2 Linearized graph is plotted | 1.00 |
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| 3 Axes labels are missing | -0.20 |
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| 4 Poor scale | -0.20 |
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| 5 Poor ticks | -0.20 |
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| 6 There is no fitting line | -0.20 |
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| 7 $\mathrm{slope}\in [-6.0,-4.0]\cdot 10^{-3} ~\mathrm{s}^{-1}$ | 0.50 |
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| 1 \[\tau \in [150,250]~\mathrm{s}\] | 0.20 |
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