| 1 The 3rd Kepler's law is written for Jupiter and the Earth | 0.40 |
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| 2 \[ R_J = R_E \left( \frac{T_J}{T_E} \right)^{2/3}\] | 0.40 |
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3
Answer \[R_J = 778 \cdot 10^6~\text{km}\] |
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| 4 The 3rd Kepler's law in general form or 2nd Newton's law for circular motion is used. | 0.50 |
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| 5 \[ \frac{M_J}{M_S} = \frac{R_M^3}{R_E^3} \frac{T_E^2}{T_0^2} \] | 0.40 |
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6
Answer \[ \frac{M_J}{M_S} = 9.54 \cdot 10^{-4} \] |
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| 1 The geometrical viewpoint is described: sum of angles or difference in angular velocities. | 0.50 |
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| 2 \[T_\text{real} = \frac{T_J T_0}{T_J-T_0}\] | 0.50 |
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1
The angular velocity of the frame is obtained \[\omega_{SJ} = \frac{2 \pi }{T_J}\] |
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| 2 \[ \omega = \frac{2\pi}{T_E} - \omega_{SJ}\] | 0.50 |
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| 3 \[\omega = 2 \pi \frac{T_J-T_E}{T_J T_E}\] | 0.50 |
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| 4 \[ v = R_E \omega\] | 0.30 |
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| 1 The Pythagorean theorem is used | 0.30 |
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| 2 \[d^2 = R_E^2 \sin^2 \theta + (R_J - R_E \cos \theta)^2\] | 0.40 |
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3
After approximation it is found that \[d = R_J - R_E \cos \theta \] |
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4
Answer \[d = R_J - R_E \cos \omega t\] |
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1
The idea connected to changes of $d$ over a period is proposed, e.g. \[T_\text{obs} = T_\text{real} + \frac{\Delta d}{c},\]where $\Delta d$ - is change in $d$ over $T_\text{real}$ |
0.80 |
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| 2 \[\dot{d} = \omega R_E \sin \omega t\] | 0.20 |
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| 3 \[ T_\text{obs} = T_\text{real} + T_\text{real} \frac{\omega R_E}{c} \sin \omega t\] | 0.30 |
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| 4 The graph is oscillating about $T_\text{real}$ function | 0.20 |
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| 5 The graph is a graph of sine | 0.20 |
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| 6 It's noticed that maximal and minimal values correspond to $\theta \approx \pm \pi/2$ | 0.20 |
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| 7 The maximum of $T_\text{obs}$ corresponds to $\theta = \pi/2$. | 0.10 |
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| 8 The minimum of $T_\text{obs}$ corresponds to $\theta = \pi/2$. | 0.10 |
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| 9 The real period is observed when $\theta=0$ | 0.20 |
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| 10 The real period is observed when $\theta=\pi$ | 0.20 |
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| 1 \[T_\text{obs,max}-T_\text{obs,min} = \frac{2 \omega R_E}{c} T_\text{real}\] | 0.50 |
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| 2 \[c = 3.03 \cdot 10^8~\text{m}/\text{s}\] | 0.50 |
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