| 1 correct result for $L$ (just magnitude is fine) | 0.10 |
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| 2 correct result for $\mu$ (just magnitude is fine) | 0.10 |
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| 3 correct result for $\gamma$ | 0.10 |
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| 1 Writing the torque formula | 0.10 |
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| 2 Realizing only the perpendicular component $L\sin \theta$ is changing | 0.10 |
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| 3 Correct magnitude for $\omega_L$ | 0.10 |
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| 4 Correct sign for $\omega_L$ | 0.10 |
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| 1 Writing the interaction energy correctly | 0.10 |
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| 2 Writing the correct magnetic field magnitude | 0.10 |
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| 3 Writing the correct magnetic field direction | 0.10 |
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| 4 Correct magnitude for $J_0$ | 0.10 |
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| 5 Correct sign for $J_0$ | 0.10 |
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| 1 Explicit understanding that $i−1$ and $i+ 1$ are the contributors for spin $i$ | 0.20 |
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| 2 Correct result for effective magnetic field | 0.10 |
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| 1 Writing the rate of change of $\vec{S}$ using the effective magnetic field | 0.10 |
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2
Correct equation |
0.20 |
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Find the relationship between $\omega$ and $k$ (known as the dispersion relation, $\omega(k)$) for the spin waves in terms of $J, S$ and $a$.
Hint: express the position of the $i$th spin as $x=a\cdot i$.
| 1 Writing traveling waves as function of $kx \pm \omega t$ (either sign is okay, either trig function or complex exponentials is okay) | 0.30 |
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| 2 Same amplitude for $S_x$ and $S_y$ | 0.20 |
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| 3 Correct phase relation between $S_x$ and $S_y$ (a difference of $\pi/2$) | 0.30 |
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| 4 Writing the correct explicit equation of motion for either $S_x$ or $S_y$ | 0.50 |
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| 5 Explicit use of $S_z \approx S$ | 0.20 |
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6
Correct final result ($\pm$ is okay) |
0.50 |
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| 1 Correct Taylor expansion result | 0.20 |
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| 2 Correct relation between momentum and wave vector | 0.10 |
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| 3 Correct relation between energy and angular frequency | 0.10 |
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| 4 Correct identification of effective mass | 0.20 |
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| 1 Conservation of momentum along $y$-axis | 0.40 |
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| 2 Conservation of momentum along $x$-axis | 0.30 |
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| 3 Conservation of energy | 0.20 |
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| 4 Relation between $E_{out}$and $E_{in}$ | 0.10 |
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5
Correct final answer (should be in either two forms at the end) $$ m_{\text{eff}} = \frac{\sin^2(\theta_{\text{in}} - \theta_\text{out})}{\cos^2 \theta_\text{out} - \cos^2 \theta_\text{in}} m_n = \frac{\sin(\theta_\text{in} - \theta_\text{out})}{\sin(\theta_\text{in} + \theta_\text{out})} m_n $$ |
0.30 |
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| 6 Other forms of answer | 0.20 |
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| 1 Use of Boltzmann factor | 0.20 |
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2
Correct Boltzmann factor for up and down (0.1 each) |
2 × 0.10 |
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| 3 Correct final result for the ratio | 0.10 |
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| 1 Deducing $\overline{s} = p_\uparrow - p_\downarrow$ | 0.20 |
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| 2 Normalization condition $p_\uparrow + p_\downarrow = 1$ | 0.10 |
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| 3 Final result for $\overline{s}$ | 0.10 |
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| 4 Correct sketches (0.2 each) | 3 × 0.20 |
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| 1 Realizing the spins minimize their energy by aligning along the same direction | 0.10 |
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| 2 Correct result (both $N −1$ and $N$ are fine) | 0.10 |
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| 1 Realizing $s_{i+1}$ can be replaced with $\overline{s}$ | 0.10 |
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| 2 Correct final result | 0.10 |
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| 1 stating $\overline{s} = \tanh (\tilde{J}_\text{eff}/k_BT)$ | 0.10 |
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| 2 Replacing $J_\text{eff}$ for $h$ in $\overline{s}$ results from C.2 | 0.20 |
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| 3 Realizing that there is one trivial solution for $\tilde{J} \ll k_B T$ | 0.20 |
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| 4 Realizing that there are two non-trivial solutions for $\tilde{J} \gg k_B T$ | 0.20 |
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| 5 Clearly stating the condition at when number of solutions changes | 0.30 |
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| 6 Correct final result for $T_c$ | 0.20 |
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| 1 Using the proper approximation for tanh | 0.10 |
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| 2 Correct non-trivial solutions for $\overline{s}$, even if not fully simplified (0.1 each) | 2 × 0.10 |
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| 3 Sketch $\overline{s}$ as the only solution above $T_c$ | 0.10 |
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4
The non trivial solutions are vertical at $T_c$ |
0.20 |
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| 5 $\overline{s} = 0$ is sketched as a solution for $T < T_c$ | 0.10 |
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6
The two non-trivial solutions monotonically increase to $\pm 1$ at $T = 0$ (0.1 each) |
2 × 0.10 |
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| 7 Either non-trivial solutions have a zero slope approaching $T = 0$. | 0.10 |
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| 1 Correct choice for $T > T_c$ (paramagnetic) | 0.10 |
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| 2 Correct choice for $T < T_c$ (ferromagnetic) | 0.10 |
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