Usually, when studying ideal gases, it is assumed that their molar heat capacity $C_V$ at constant volume is a constant, which is independent of temperature and determined by the number of atoms in a gas molecule. However, in reality, this heat capacity can change. At very low temperatures, the thermal energy turns out to be insufficient to cause rotational motion of the molecules, and they can be considered monatomic. Therefore, the heat capacity at low temperatures turns out to be lower than at high temperatures. In this problem, we will consider several cases of variable heat capacity. At the same time, the equation of state of an ideal gas (that is, the relationship between pressure, volume, and temperature) does not change.
In this part, we will assume that over the entire temperature range of interest, the heat capacity of one mole of gas at constant volume depends on temperature as $C_{V} = C_0 + a T$ ($C_0, a > 0$ are constants, independent of temperature). All processes are carried out with one mole of gas. In all answers for this part, you may use $C_0$, $a$ and the molar gas constant $R$.
A5
1.50
Let's consider a cycle $123$. The pressure is proportiaonal to the volume along $1-2$, $2-3$ is isochoric, $3-1$ is isobaric. It's known that $V_2 = 2 V_1$ and heat capacity at constant volume in points $1$ and $2$ are related by the ration $C_{V2} = 1.5 C_{V1}$.
Determine a thermal efficiency of the cycle. Consider that $C_0=3R/2$.
Let us propose a more realistic model for the heat capacity of a gas. For $T < T_1$, the heat capacity $C_V$ is constant and equal to that of monoatomic gas $C_1=3R/2$. In the range $ T_1 < T < T_2 $, the heat capcity increases linearly, reaching the value $C_2=5R/2$ (corresponds to a diatomic gas) at $T=T_2$. For $T>T_2$, the heat capacity remains constant. Let's assume that $T_2 = 2 T_1$.
The initial temperature of gas is $T_A=T_1/2$. We will increase the gas temperature to $T_B=3T_1$ via different paths.